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A bag has 3 red and 5 green marbles, 2 are picked at random, P(both…

Step by step, with the reason for every step · Probability with counting · Probability

Step by step

The question

Question: A bag has 3 red and 5 green marbles.

2 marbles are picked at random.

What is the probability that both are green?

The probability is the number of ways we want, over all the ways.

P(all green) = ways we wantall ways

P stands for probability.

P = probability

1 Order: yes or no

Does order matter?

No.

Picking Ann, then Bo, is the same group as Bo, then Ann.

So we count groups: combinations.

= a group: order does not matter → nCr

2 Count all the ways

8 C 2: the top 2 numbers from 8 down, over 2 factorial.

all = 8C2 = 8 × 72 × 1

Before we multiply, we make the numbers smaller.

8 on top and 2 at the bottom: 8 divided by 2 is 4.

What is left: 4 times 7.

That is 28 ways.

all = 28
4 × 7 = 28

3 Count the ways we want

5 C 2: the top 2 numbers from 5 down, over 2 factorial.

green = 5C2 = 5 × 42 × 1

Before we multiply, we make the numbers smaller.

4 on top and 2 at the bottom: 4 divided by 2 is 2.

What is left: 5 times 2.

That is 10 ways.

green = 10
5 × 2 = 10

4 Write the fraction

10 ways we want, out of 28.

P(all green) = 1028

Careful!

The top and the bottom must count the same way: both are groups, with C.

Careful: count groups on top AND at the bottom

5 Simplify

Both 10 and 28 can be divided by 2.

That makes it simpler.

P(all green) = 10 ÷ 228 ÷ 2

So it is 5/14.

P(all green) = 514

6 Check

Let's check another way: pick one at a time.

The first: 5 out of 8.

Then one fewer of each.

Multiplied, that is 5/14.

The same.

So the answer is right!

58 × 47 = 514

Let's look back.

First: order: yes or no.

Then: count all the ways.

Then: count the ways we want.

Then: write the fraction.

Then: simplify.

Last: check.

Answer
P(all green) = 514

Your turn

Try this one yourself, then check:

Show the answer
P(all green) = 34

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