Steply

A team has 4 seniors and 6 juniors, 2 are picked at random, P(both…

Step by step, with the reason for every step · Probability with counting · Probability

Step by step

The question

Question: A team has 4 seniors and 6 juniors.

2 of them are picked at random.

What is the probability that both are seniors?

The probability is the number of ways we want, over all the ways.

P(all seniors) = ways we wantall ways

P stands for probability.

P = probability

1 Order: yes or no

Does order matter?

No.

Picking Ann, then Bo, is the same group as Bo, then Ann.

So we count groups: combinations.

= a group: order does not matter → nCr

2 Count all the ways

10 C 2: the top 2 numbers from 10 down, over 2 factorial.

all = 10C2 = 10 × 92 × 1

Before we multiply, we make the numbers smaller.

10 on top and 2 at the bottom: 10 divided by 2 is 5.

What is left: 5 times 9.

That is 45 ways.

all = 45
5 × 9 = 45

3 Count the ways we want

4 C 2: the top 2 numbers from 4 down, over 2 factorial.

seniors = 4C2 = 4 × 32 × 1

Before we multiply, we make the numbers smaller.

4 on top and 2 at the bottom: 4 divided by 2 is 2.

What is left: 2 times 3.

That is 6 ways.

seniors = 6
2 × 3 = 6

4 Write the fraction

6 ways we want, out of 45.

P(all seniors) = 645

Careful!

The top and the bottom must count the same way: both are groups, with C.

Careful: count groups on top AND at the bottom

5 Simplify

Both 6 and 45 can be divided by 3.

That makes it simpler.

P(all seniors) = 6 ÷ 345 ÷ 3

So it is 2/15.

P(all seniors) = 215

6 Check

Let's check another way: pick one at a time.

The first: 4 out of 10.

Then one fewer of each.

Multiplied, that is 2/15.

The same.

So the answer is right!

410 × 39 = 215

Let's look back.

First: order: yes or no.

Then: count all the ways.

Then: count the ways we want.

Then: write the fraction.

Then: simplify.

Last: check.

Answer
P(all seniors) = 215

Your turn

Try this one yourself, then check:

Show the answer
P(all seniors) = 112

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