Steply

9 horses race, a bet picks the 1st and 2nd at random, P(the bet wins)

Step by step, with the reason for every step · Probability with counting · Probability

Step by step

The question

Question: 9 horses run a race.

A bet picks the 1st and 2nd places, in order, at random.

What is the probability that the bet wins?

The probability is the number of ways we want, over all the ways.

P(bet wins) = ways we wantall ways

P stands for probability.

P = probability

1 Order: yes or no

Does order matter?

Yes.

A first, B second is not B first, A second.

So we count permutations.

= places: order matters → nPr

2 Count all the ways

9 P 2: 9 choices for the first place, then 8 for the second.

all = 9P2 = 9 × 8

9 times 8 is 72 ways.

all = 72

3 Count the ways we want

Only one order wins: the real 1st and 2nd.

So 1 way.

we want = 1

4 Write the fraction

1 way we want, out of 72.

P(bet wins) = 172

Careful!

Not 9 C 2: that counts groups.

Here the places are different, so order matters.

Careful: not 136 ✗

5 Check

Let's check another way: one place at a time.

The right 1st: 1 out of 9.

Then the right 2nd: 1 out of the 8 left.

Multiplied, that is 1/72.

The same.

So the answer is right!

19 × 18 = 172

Let's look back.

First: order: yes or no.

Then: count all the ways.

Then: count the ways we want.

Then: write the fraction.

Last: check.

Answer
Careful: not 136 ✗

Your turn

Try this one yourself, then check:

Show the answer
P(bet wins) = 130

More from Probability with counting

The whole lesson: Probability with counting →