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A class has 7 boys and 5 girls, 2 are picked at random, P(1 boy and…

Step by step, with the reason for every step · Probability with counting · Probability

Step by step

The question

Question: A class has 7 boys and 5 girls.

2 of them are picked at random.

What is the probability that 1 is a boy and 1 is a girl?

The probability is the number of ways we want, over all the ways.

P(1 boy, 1 girl) = ways we wantall ways

P stands for probability.

P = probability

1 Order: yes or no

Does order matter?

No.

Picking Ann, then Bo, is the same group as Bo, then Ann.

So we count groups: combinations.

= a group: order does not matter → nCr

2 Count all the ways

12 C 2: the top 2 numbers from 12 down, over 2 factorial.

all = 12C2 = 12 × 112 × 1

Before we multiply, we make the numbers smaller.

12 on top and 2 at the bottom: 12 divided by 2 is 6.

What is left: 6 times 11.

That is 66 ways.

all = 66
6 × 11 = 66

3 Count the ways we want

Picking 1 of 7 boys: 7 ways.

boys = 7C1 = 7

Picking 1 of 5 girls: 5 ways.

girls = 5C1 = 5

Each choice of boys goes with each choice of girls.

So we multiply: 7 times 5 is 35.

we want = 7 × 5 = 35

Careful!

We need both at the same time: boys and girls.

And means multiply, not add.

Careful: not 7 + 5 ✗

4 Write the fraction

35 ways we want, out of 66.

P(1 boy, 1 girl) = 3566

5 Check

Let's check another way: pick one at a time, in the order B, G.

Multiplied, that is 35/132.

BG: 712 × 511 = 35132

But the 1 boy and the 1 girl can come in 2 orders, each just as likely.

2 times that is 35/66.

The same.

So the answer is right!

2 orders: 2 × 35132 = 3566

Let's look back.

First: order: yes or no.

Then: count all the ways.

Then: count the ways we want.

Then: write the fraction.

Last: check.

Answer
P(1 boy, 1 girl) = 3566

Your turn

Try this one yourself, then check:

Show the answer
P(1 boy, 1 girl) = 4891

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