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3 cards are dealt from 52, P(all kings)

Step by step, with the reason for every step · Probability with counting · Probability

Step by step

The question

Question: 3 cards are dealt from a deck of 52.

What is the probability that all 3 are kings?

The probability is the number of ways we want, over all the ways.

P(all kings) = ways we wantall ways

P stands for probability.

P = probability

1 Order: yes or no

Does order matter?

No.

A hand of cards is the same hand in any order.

So we count groups: combinations.

= a hand: order does not matter → nCr

2 Count all the ways

52 C 3: the top 3 numbers from 52 down, over 3 factorial.

all = 52C3 = 52 × 51 × 503 × 2 × 1

Before we multiply, we make the numbers smaller.

51 and 3 both divide by 3: 17.

52 and 2 both divide by 2: 26.

What is left is 26 times 17 times 50.

all = 26 × 17 × 50

26 times 17 is 442.

442 times 50 is 22,100.

26 × 17 = 442
442 × 50 = 22,100

So there are 22,100 ways.

all = 22,100

3 Count the ways we want

4 C 3: the top 3 numbers from 4 down, over 3 factorial.

kings = 4C3 = 4 × 3 × 23 × 2 × 1

Before we multiply, we make the numbers smaller.

3 and 3 both divide by 3: 1.

4 and 2 both divide by 2: 2.

What is left: 2 times 2.

That is 4 ways.

kings = 4
2 × 2 = 4

4 Write the fraction

4 ways we want, out of 22,100.

P(all kings) = 422,100

Careful!

The top and the bottom must count the same way: both are groups, with C.

Careful: count groups on top AND at the bottom

The numbers are big, so we use a decimal: 4 divided by 22,100 is about 0.000181.

Very small!

P(all kings) ≈ 0.000181

5 Check

Let's check another way: pick one at a time.

The first card: 4 out of 52.

Then one fewer each time.

Multiplied, that is about 0.000181.

The same.

So the answer is right!

452 × 351 × 250 ≈ 0.000181

Let's look back.

First: order: yes or no.

Then: count all the ways.

Then: count the ways we want.

Then: write the fraction.

Last: check.

Answer
P(all kings) ≈ 0.000181

Your turn

Try this one yourself, then check:

Show the answer
P(all red cards) ≈ 0.118

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