Steply

8 runners race, a bet picks the 1st, 2nd and 3rd at random, P(the…

Step by step, with the reason for every step · Probability with counting · Probability

Step by step

The question

Question: 8 runners run a race.

A bet picks the 1st, 2nd and 3rd places, in order, at random.

What is the probability that the bet wins?

The probability is the number of ways we want, over all the ways.

P(bet wins) = ways we wantall ways

P stands for probability.

P = probability

1 Order: yes or no

Does order matter?

Yes.

A first, B second is not B first, A second.

So we count permutations.

= places: order matters → nPr

2 Count all the ways

8 P 3: 8 choices for the first place, then 7 for the second, then 6.

all = 8P3 = 8 × 7 × 6

8 times 7 times 6 is 336 ways.

all = 336

3 Count the ways we want

Only one order wins: the real 1st, 2nd and 3rd.

So 1 way.

we want = 1

4 Write the fraction

1 way we want, out of 336.

P(bet wins) = 1336

Careful!

Not 8 C 3: that counts groups.

Here the places are different, so order matters.

Careful: not 156 ✗

5 Check

Let's check another way: one place at a time.

The right 1st: 1 out of 8.

Then the right 2nd: 1 out of the 7 left, and 1 out of 6.

Multiplied, that is 1/336.

The same.

So the answer is right!

18 × 17 × 16 = 1336

Let's look back.

First: order: yes or no.

Then: count all the ways.

Then: count the ways we want.

Then: write the fraction.

Last: check.

Answer
Careful: not 156 ✗

Your turn

Try this one yourself, then check:

Show the answer
P(bet wins) = 1210

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