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Are (1, 0, 2) and (2, 5, -1) orthogonal

Step by step, with the reason for every step · Dot product and length · Linear Algebra

Step by step

The question

Question: are (1, 0, 2) and (2, 5, −1) orthogonal?

u = [1; 0; 2], v = [2; 5; −1]

Orthogonal means perpendicular: at a right angle.

Two vectors are orthogonal exactly when their dot product is 0.

orthogonal: at a right angle (perpendicular)
u • v = 0

1 Find the dot product

Matching entries multiplied, then added: 1 × 2 + 0 × 5 + 2 × (−1).

u • v = 1 × 2 + 0 × 5 + 2 × (−1)

We work out each times.

u • v = 2 + 0 − 2

Then we add: u • v = 0.

u • v = 0

2 Compare with 0

The dot product is 0.

So yes: the vectors are orthogonal.

= orthogonal

Careful!

Only a dot product of exactly 0 means orthogonal.

Any other number, even a small one, means not.

Careful: orthogonal: the dot product is exactly 0

3 Check

Let's check with Pythagoras.

At a right angle, the length of u squared plus the length of v squared equals the length of u plus v, squared.

right angle: ‖u‖2 + ‖v‖2 = ‖u + v‖2

The length squared is the entries squared, added.

For u: 5.

‖u‖² = 12 + 02 + 22 = 1 + 0 + 4 = 5

For v: 30.

‖v‖² = 22 + 52 + (−1)2 = 4 + 25 + 1 = 30

u plus v: (3, 5, 1).

u + v = [3; 5; 1]

Its length squared: 35.

‖u + v‖² = 32 + 52 + 12 = 9 + 25 + 1 = 35

5 plus 30 is 35, the same as 35.

Pythagoras works: a right angle.

So the answer is right!

5 + 30 = 35 = 35

Let's look back.

First: find the dot product.

Then: compare with 0.

Last: check.

Answer
Careful: orthogonal: the dot product is exactly 0

Your turn

Try this one yourself, then check:

Orthogonal? [1; 2; 1] and [2; 3; −8]
Show the answer
orthogonal

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