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Are (3, -2, 1) and (1, 2, 1) perpendicular

Step by step, with the reason for every step · Dot product and length · Linear Algebra

Step by step

The question

Question: are (3, −2, 1) and (1, 2, 1) perpendicular?

u = [3; −2; 1], v = [1; 2; 1]

Orthogonal means perpendicular: at a right angle.

Two vectors are orthogonal exactly when their dot product is 0.

orthogonal: at a right angle (perpendicular)
u • v = 0

1 Find the dot product

Matching entries multiplied, then added: 3 × 1 + (−2) × 2 + 1 × 1.

u • v = 3 × 1 + (−2) × 2 + 1 × 1

We work out each times.

u • v = 3 − 4 + 1

Then we add: u • v = 0.

u • v = 0

2 Compare with 0

The dot product is 0.

So yes: the vectors are orthogonal.

= orthogonal

Careful!

Only a dot product of exactly 0 means orthogonal.

Any other number, even a small one, means not.

Careful: orthogonal: the dot product is exactly 0

3 Check

Let's check with Pythagoras.

At a right angle, the length of u squared plus the length of v squared equals the length of u plus v, squared.

right angle: ‖u‖2 + ‖v‖2 = ‖u + v‖2

The length squared is the entries squared, added.

For u: 14.

‖u‖² = 32 + (−2)2 + 12 = 9 + 4 + 1 = 14

For v: 6.

‖v‖² = 12 + 22 + 12 = 1 + 4 + 1 = 6

u plus v: (4, 0, 2).

u + v = [4; 0; 2]

Its length squared: 20.

‖u + v‖² = 42 + 02 + 22 = 16 + 0 + 4 = 20

14 plus 6 is 20, the same as 20.

Pythagoras works: a right angle.

So the answer is right!

14 + 6 = 20 = 20

Let's look back.

First: find the dot product.

Then: compare with 0.

Last: check.

Answer
Careful: orthogonal: the dot product is exactly 0

Your turn

Try this one yourself, then check:

Orthogonal? [3; −1; 1] and [3; 1; −8]
Show the answer
orthogonal

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