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Area of rectangle with corners (0, 0), (6, 0), (6, 2), (0, 2)

Step by step, with the reason for every step · Polygons on the grid · Algebra 1

Step by step

The question

Question: find the area of the rectangle with corners (0, 0), (6, 0), (6, 2), (0, 2).

rectangle: (0, 0), (6, 0), (6, 2), (0, 2)

1 Plot the points

We put the corners on the grid.

Corner A is (0, 0).

And so on.

We join them in order.

2 Find the side lengths

A B: the same y, so it goes across.

Its length is the bigger x minus the smaller: 6 minus 0 is 6.

= AB: 6 − 0 = 6

B C: the same x, so it goes up and down.

Its length is the bigger y minus the smaller: 2 minus 0 is 2.

= BC: 2 − 0 = 2

3 Area

The area of a rectangle is length times width.

= area = length × width

Careful!

Adding the sides gives the perimeter, the way round.

The area is the squares inside.

Careful: not 6 + 2 + 6 + 2 = 16 ✗

6 times 2 is 12 square units.

= area = 6 × 2 = 12 square units

4 Check

Let's check: count the squares inside.

2 rows of 6 squares: 12.

So the answer is right!

2 rows of 6 squares = 12 squares

Let's look back.

First: plot the points.

Then: find the side lengths.

Then: area.

Last: check.

Answer
= area = 6 × 2 = 12 square units

Your turn

Try this one yourself, then check:

rectangle: (0, 1), (7, 1), (7, 2), (0, 2)
Show the answer
7 square units

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