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Area of square with corners (2, 1), (5, 1), (5, 4), (2, 4)

Step by step, with the reason for every step · Polygons on the grid · Algebra 1

Step by step

The question

Question: find the area of the square with corners (2, 1), (5, 1), (5, 4), (2, 4).

square: (2, 1), (5, 1), (5, 4), (2, 4)

1 Plot the points

We put the corners on the grid.

Corner A is (2, 1).

And so on.

We join them in order.

2 Find the side lengths

A B: the same y, so it goes across.

Its length is the bigger x minus the smaller: 5 minus 2 is 3.

= AB: 5 − 2 = 3

B C: the same x, so it goes up and down.

Its length is the bigger y minus the smaller: 4 minus 1 is 3.

= BC: 4 − 1 = 3

3 Area

The area of a square is length times width.

= area = length × width

Careful!

Adding the sides gives the perimeter, the way round.

The area is the squares inside.

Careful: not 3 + 3 + 3 + 3 = 12 ✗

3 times 3 is 9 square units.

= area = 3 × 3 = 9 square units

4 Check

Let's check: count the squares inside.

3 rows of 3 squares: 9.

So the answer is right!

3 rows of 3 squares = 9 squares

Let's look back.

First: plot the points.

Then: find the side lengths.

Then: area.

Last: check.

Answer
= area = 3 × 3 = 9 square units

Your turn

Try this one yourself, then check:

square: (2, 2), (4, 2), (4, 4), (2, 4)
Show the answer
4 square units

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