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Area of triangle with corners (0, 0), (6, 0), (2, 4)

Step by step, with the reason for every step · Polygons on the grid · Algebra 1

Step by step

The question

Question: find the area of the triangle with corners (0, 0), (6, 0), (2, 4).

triangle: (0, 0), (6, 0), (2, 4)

1 Plot the points

We put the corners on the grid.

Corner A is (0, 0).

And so on.

We join them in order.

2 Find the base and height

base A B: the same y, so it goes across.

Its length is the bigger x minus the smaller: 6 minus 0 is 6.

= base AB: 6 − 0 = 6

The height goes straight down from C to the base line.

It goes from y = 4 to y = 0: 4 units.

= height: 4 − 0 = 4

3 Area

The area of a triangle is a half times base times height.

= area = 12 × base × height

Careful!

Base times height is the whole rectangle around it.

The triangle is half of that.

Careful: not 6 × 4 = 24 ✗

Half of 6 times 4 is 12 square units.

= area = 12 × 6 × 4 = 12 square units

4 Check

Let's check: the rectangle around the base and the height is 6 by 4: 24 squares.

The triangle takes half of it: 12.

So the answer is right!

rectangle 6 × 4 = 24, half = 12

Let's look back.

First: plot the points.

Then: find the base and height.

Then: area.

Last: check.

Answer
= area = 12 × 6 × 4 = 12 square units

Your turn

Try this one yourself, then check:

triangle: (2, 1), (8, 1), (4, 5)
Show the answer
12 square units

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