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Perimeter of rectangle with corners (2, 3), (7, 3), (7, 5), (2, 5)

Step by step, with the reason for every step · Polygons on the grid · Algebra 1

Step by step

The question

Question: find the perimeter of the rectangle with corners (2, 3), (7, 3), (7, 5), (2, 5).

rectangle: (2, 3), (7, 3), (7, 5), (2, 5)

1 Plot the points

We put the corners on the grid.

Corner A is (2, 3).

And so on.

We join them in order.

2 Find the side lengths

A B: the same y, so it goes across.

Its length is the bigger x minus the smaller: 7 minus 2 is 5.

= AB: 7 − 2 = 5

B C: the same x, so it goes up and down.

Its length is the bigger y minus the smaller: 5 minus 3 is 2.

= BC: 5 − 3 = 2

3 Perimeter

The perimeter is the way round: all four sides.

= perimeter = all four sides

Careful!

Not just two sides.

The way round has four sides.

Careful: not 5 + 2 = 7 ✗

5 plus 2 plus 5 plus 2 is 14 units.

= perimeter = 5 + 2 + 5 + 2 = 14 units

4 Check

Let's check: opposite sides are the same.

So it is 2 times 5 plus 2: 2 times 7 is 14.

So the answer is right!

2 × (5 + 2) = 2 × 7 = 14

Let's look back.

First: plot the points.

Then: find the side lengths.

Then: perimeter.

Last: check.

Answer
= perimeter = 5 + 2 + 5 + 2 = 14 units

Your turn

Try this one yourself, then check:

rectangle: (3, 2), (9, 2), (9, 4), (3, 4)
Show the answer
16 units

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