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Area of rectangle with corners (-3, 1), (2, 1), (2, 5), (-3, 5)

Step by step, with the reason for every step · Polygons on the grid · Algebra 1

Step by step

The question

Question: find the area of the rectangle with corners (−3, 1), (2, 1), (2, 5), (−3, 5).

rectangle: (−3, 1), (2, 1), (2, 5), (−3, 5)

1 Plot the points

We put the corners on the grid.

Corner A is (−3, 1).

And so on.

We join them in order.

2 Find the side lengths

A B: the same y, so it goes across.

Its length is the bigger x minus the smaller: 2 minus −3 is 5.

= AB: 2 − (−3) = 5

Careful!

−3 is on the other side of 0.

Minus a negative is plus: 2 plus 3.

Careful: not 2 − 3 = -1 ✗

B C: the same x, so it goes up and down.

Its length is the bigger y minus the smaller: 5 minus 1 is 4.

= BC: 5 − 1 = 4

3 Area

The area of a rectangle is length times width.

= area = length × width

5 times 4 is 20 square units.

= area = 5 × 4 = 20 square units

4 Check

Let's check: count the squares inside.

4 rows of 5 squares: 20.

So the answer is right!

4 rows of 5 squares = 20 squares

Let's look back.

First: plot the points.

Then: find the side lengths.

Then: area.

Last: check.

Answer
= area = 5 × 4 = 20 square units

Your turn

Try this one yourself, then check:

rectangle: (−5, 0), (0, 0), (0, 4), (−5, 4)
Show the answer
20 square units

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