Steply

Double integral of x^2 over 0 ≤ x ≤ 2, 0 ≤ y ≤ 2x

Step by step, with the reason for every step · Double integrals over general regions · Calculus 3

Step by step

The question

Question: find the double integral of x² over 0 ≤ x ≤ 2, 0 ≤ y ≤ 2x.

∫ ∫ x2 dA, 0 ≤ x ≤ 2, 0 ≤ y ≤ 2x

1 Draw the region

Draw the grid.

Draw y = 2x

and y = 0.

The region is between them.

2 Find the limits

Take a thin upright strip.

On it, y goes from the bottom curve up to the top curve.

So inside, y goes from 0 to 2x.

Outside, x goes from 0 to 2.

∫ ∫ x2 dA = ∫ from 0 to 2 of ∫ from 0 to 2x of x2 dy dx

Careful!

The inside integral is dy, so its limits are the y limits.

They may have x in them.

The outside limits are only numbers.

Careful: dy inside: the y limits go inside

3 The inner integral

Inside first: integrate in y.

x stays fixed, like a plain number.

Integrate each term: the power goes up by 1, and we divide by the new power.

∫ from 0 to 2x of x2 dy = x2y from 0 to 2x

Put in the top y = 2x, then take away the bottom y = 0.

∫ from 0 to 2x of x2 dy = x2(2x) − x2(0)

The bottom part is 0.

So it is 2x³.

∫ from 0 to 2x of x2 dy = 2x3

4 The outer integral

Now the outside integral, in x.

Its limits are numbers.

Integrate each term: the power goes up by 1, and we divide by the new power.

∫ from 0 to 2 of 2x3 dx = x42 from 0 to 2

Put in the top x = 2, then take away the bottom x = 0.

∫ from 0 to 2 of 2x3 dx = (2)42 − (0)42

The bottom part is 0.

So it is 8.

∫ from 0 to 2 of 2x3 dx = 8

5 Check

Let's check if it makes sense.

The region's area is 4.

On it, f goes from 0 to 4.

area = 4, f from 0 to 4

So the answer must be between 0 and 16.

8 is.

Right!

0 ≤ 8 ≤ 16

Let's look back.

First: draw the region.

Then: find the limits.

Then: the inner integral.

Then: the outer integral.

Last: check.

Answer
∫ from 0 to 2 of 2x3 dx = 8

Your turn

Try this one yourself, then check:

Find the double integral of ∫ ∫ 2x2 dA, 0 ≤ x ≤ 2, 0 ≤ y ≤ 2x
Show the answer
16

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