Steply

Double integral of y over the region between y = x and y = 4x - x^2

Step by step, with the reason for every step · Double integrals over general regions · Calculus 3

Step by step

The question

Question: find the double integral of y over the region between y = x and y = 4x − x².

∫ ∫ y dA, between y = x and y = 4x − x²

1 Draw the region

Draw the grid.

Draw y = 4x − x²

and y = x.

The region is between them.

Where do they meet?

Where the two heights are equal.

4x − x2 = x

Bring everything to one side.

3x − x2 = 0

Take out x.

x(3 − x) = 0

So they meet at x = 0 and x = 3.

x = 0 or x = 3

Which is on top?

Try x = 1.5: y = 4x − x² is higher.

x = 1.5: 4x − x² → 3.75, x → 1.5

2 Find the limits

Take a thin upright strip.

On it, y goes from the bottom curve up to the top curve.

So inside, y goes from x to 4x − x².

Outside, x goes from 0 to 3.

∫ ∫ y dA = ∫ from 0 to 3 of ∫ from x to 4x − x² of y dy dx

Careful!

The inside integral is dy, so its limits are the y limits.

They may have x in them.

The outside limits are only numbers.

Careful: dy inside: the y limits go inside

3 The inner integral

Inside first: integrate in y.

x stays fixed, like a plain number.

Integrate each term: the power goes up by 1, and we divide by the new power.

∫ from x to 4x − x² of y dy = y22 from x to 4x − x²

Put in the top y = 4x − x², then take away the bottom y = x.

∫ from x to 4x − x² of y dy = (4x − x2)22 − (x)22

Work out each part.

∫ from x to 4x − x² of y dy = 8x2 − 4x3 + x42 − x22

So it is 15x² over 2 − 4x³ + x⁴ over 2.

∫ from x to 4x − x² of y dy = 15x22 − 4x3 + x42

4 The outer integral

Now the outside integral, in x.

Its limits are numbers.

Integrate each term: the power goes up by 1, and we divide by the new power.

∫ from 0 to 3 of (15x22 − 4x3 + x42) dx = [5x32 − x4 + x510] from 0 to 3

Put in the top x = 3, then take away the bottom x = 0.

∫ from 0 to 3 of (15x22 − 4x3 + x42) dx = (5(3)32 − (3)4 + (3)510) − (5(0)32 − (0)4 + (0)510)

The bottom part is 0.

So it is 54/5.

∫ from 0 to 3 of (15x22 − 4x3 + x42) dx = 545

5 Check

Let's check if it makes sense.

The region's area is 9/2.

On it, f goes from 0 to 4.

area = 9/2, f from 0 to 4

So the answer must be between 0 and 17.997.

10.8 is.

Right!

0 ≤ 10.8 ≤ 17.997

Let's look back.

First: draw the region.

Then: find the limits.

Then: the inner integral.

Then: the outer integral.

Last: check.

Answer
∫ from 0 to 3 of (15x22 − 4x3 + x42) dx = 545

Your turn

Try this one yourself, then check:

∫ ∫ 2y dA, between y = x and y = 4x − x²
Show the answer
1085

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