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Limit as x -> infinity of (x^3 - 1)/(2x^2 + 5)

Step by step, with the reason for every step · Limits at infinity · Calculus

Step by step

The question

Question: find the limit as x → ∞ of (x³ − 1)/(2x² + 5).

lim x → ∞ x3 − 12x2 + 5 =

1 Find the highest powers

x goes to infinity: x gets huge, bigger than any number.

Then the highest power wins.

On top it is x³.

At the bottom it is 2x².

See it with x = 1000.

x³ is 1,000,000,000.

The other part is tiny next to that.

x = 1000: x³ = 1,000,000,000
−1: tiny next to it

2 Keep only those

So we keep only x³ over 2x².

= lim x → ∞ x² × x2x²

Split the bigger power: x³ is x² × x.

x³ = x² × x

x² over x² is 1.

Cross them out.

Write what is left.

x is still on top.

= lim x → ∞ 12x

When x is huge, this is huge too.

It grows without end.

x = 1000: x = 1,000

Careful!

The top grows faster than the bottom.

So the fraction never settles on a number.

Careful: top power bigger → no number

It grows without end.

We write ∞: there is no number it gets close to.

= ∞

3 Check

Let's check: put x = 1000 into the whole fraction.

We get about 500.

x = 1000: f(x) ≈ 500

With x = 10000 it is about 5000.

It keeps growing.

Right!

x = 10000: f(x) ≈ 5000

Let's look back.

First: find the highest powers.

Then: keep only those.

Last: check.

Answer
= ∞

Your turn

Try this one yourself, then check:

lim x → ∞ x3 − 12x2 + 10
Show the answer
limit = ∞

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