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Mean of grouped data 0-1: 5, 1-2: 8, 2-3: 4, 3-4: 3

Step by step, with the reason for every step · Mean of grouped data · Statistics

Step by step

The question

Question: find the mean of the grouped data with classes 0 to 1, 1 to 2, 2 to 3 and 3 to 4, and frequencies 5, 8, 4 and 3.

Mean of the grouped data

Each class is a range of numbers.

f is how many numbers are in it.

So 5 numbers are from 0 to 1.

f = how many, m = the middle of the class

1 Find the midpoints

We don't know the numbers themselves.

So each class uses its middle, m: the midpoint.

m = (0 + 1) ÷ 2 = 0.5

The middle of 0 and 1: add them, divide by 2.

0.5.

Next: 1.5.

Each midpoint is 1 more.

And so on.

2 Multiply m × f

Each number in a class counts as its midpoint.

So a class adds up to m times f.

0.5 times 5 is 2.5.

1.5 times 8 is 12.

The same for every row.

3 Add the columns

The f column: 20 numbers in all.

5 + 8 + 4 + 3 = 20

The m × f column: 35.

That is about the total of all the numbers.

2.5 + 12 + 10 + 10.5 = 35

4 Share equally

The mean shares the total equally: 35 divided by 20.

mean ≈ 3520

It is only an estimate: the midpoints stand in for the real numbers.

≈ : an estimate, from the midpoints

Careful!

Not divided by the 4 classes.

There are 20 numbers.

Careful: not 354 ✗

35 divided by 20 is 1.75.

mean ≈ 1.75

The books round to one more decimal place than the data.

So the mean is about 1.8.

mean ≈ 1.8
1 decimal place: 1 more than the data

5 Check

Let's check: 1.8 times 20 is about 35, the total.

1.8 × 20 ≈ 36

And the mean is between the first and the last midpoints.

So it makes sense!

0.5 < 1.8 < 3.5

Let's look back.

First: find the midpoints.

Then: multiply m × f.

Then: add the columns.

Then: share equally.

Last: check.

Answer
1 decimal place: 1 more than the data

Your turn

Try this one yourself, then check:

Mean of 0–1: 4, 1–2: 6, 2–3: 5, 3–4: 5
Show the answer
mean ≈ 2.1

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