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Mean of grouped data 20-24: 6, 25-29: 9, 30-34: 7, 35-39: 4, 40-44: 1

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Step by step

The question

Question: find the mean of the grouped data with classes 20 to 24, 25 to 29, 30 to 34, 35 to 39 and 40 to 44, and frequencies 6, 9, 7, 4 and 1.

Mean of the grouped data

Each class is a range of numbers.

f is how many numbers are in it.

So 6 numbers are from 20 to 24.

f = how many, m = the middle of the class

1 Find the midpoints

We don't know the numbers themselves.

So each class uses its middle, m: the midpoint.

m = (20 + 24) ÷ 2 = 22

The middle of 20 and 24: add them, divide by 2.

22.

Next: 27.

Each midpoint is 5 more.

And so on.

2 Multiply m × f

Each number in a class counts as its midpoint.

So a class adds up to m times f.

22 times 6 is 132.

27 times 9 is 243.

The same for every row.

3 Add the columns

The f column: 27 numbers in all.

6 + 9 + 7 + 4 + 1 = 27

The m × f column: 789.

That is about the total of all the numbers.

132 + 243 + 224 + 148 + 42 = 789

4 Share equally

The mean shares the total equally: 789 divided by 27.

mean ≈ 78927

It is only an estimate: the midpoints stand in for the real numbers.

≈ : an estimate, from the midpoints

Careful!

Not divided by the 5 classes.

There are 27 numbers.

Careful: not 7895 ✗

789 divided by 27 is 29.2222.

mean ≈ 29.2222

The books round to one more decimal place than the data.

So the mean is about 29.2.

mean ≈ 29.2
1 decimal place: 1 more than the data

5 Check

Let's check: 29.2 times 27 is about 789, the total.

29.2 × 27 ≈ 788.4

And the mean is between the first and the last midpoints.

So it makes sense!

22 < 29.2 < 42

Let's look back.

First: find the midpoints.

Then: multiply m × f.

Then: add the columns.

Then: share equally.

Last: check.

Answer
1 decimal place: 1 more than the data

Your turn

Try this one yourself, then check:

Mean of 25–29: 8, 30–34: 10, 35–39: 8, 40–44: 3, 45–49: 2
Show the answer
mean ≈ 33.9

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