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Mean of grouped data 100-120: 4, 120-140: 9, 140-160: 5, 160-180: 2

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The question

Question: find the mean of the grouped data with classes 100 to 120, 120 to 140, 140 to 160 and 160 to 180, and frequencies 4, 9, 5 and 2.

Mean of the grouped data

Each class is a range of numbers.

f is how many numbers are in it.

So 4 numbers are from 100 to 120.

f = how many, m = the middle of the class

1 Find the midpoints

We don't know the numbers themselves.

So each class uses its middle, m: the midpoint.

m = (100 + 120) ÷ 2 = 110

The middle of 100 and 120: add them, divide by 2.

110.

Next: 130.

Each midpoint is 20 more.

And so on.

2 Multiply m × f

Each number in a class counts as its midpoint.

So a class adds up to m times f.

110 times 4 is 440.

130 times 9 is 1170.

The same for every row.

3 Add the columns

The f column: 20 numbers in all.

4 + 9 + 5 + 2 = 20

The m × f column: 2700.

That is about the total of all the numbers.

440 + 1170 + 750 + 340 = 2700

4 Share equally

The mean shares the total equally: 2700 divided by 20.

mean ≈ 270020

It is only an estimate: the midpoints stand in for the real numbers.

≈ : an estimate, from the midpoints

Careful!

Not divided by the 4 classes.

There are 20 numbers.

Careful: not 27004 ✗

2700 divided by 20 is 135.

mean ≈ 135

5 Check

Let's check: 135 times 20 is 2700, the total.

135 × 20 = 2700

And the mean is between the first and the last midpoints.

So it makes sense!

110 < 135 < 170

Let's look back.

First: find the midpoints.

Then: multiply m × f.

Then: add the columns.

Then: share equally.

Last: check.

Answer
mean ≈ 135

Your turn

Try this one yourself, then check:

Mean of 140–160: 5, 160–180: 6, 180–200: 3, 200–220: 1
Show the answer
mean ≈ 170

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