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Mean of grouped data 15-25: 3, 25-35: 5, 35-45: 8, 45-55: 6, 55-65: 2

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Step by step

The question

Question: find the mean of the grouped data with classes 15 to 25, 25 to 35, 35 to 45, 45 to 55 and 55 to 65, and frequencies 3, 5, 8, 6 and 2.

Mean of the grouped data

Each class is a range of numbers.

f is how many numbers are in it.

So 3 numbers are from 15 to 25.

f = how many, m = the middle of the class

1 Find the midpoints

We don't know the numbers themselves.

So each class uses its middle, m: the midpoint.

m = (15 + 25) ÷ 2 = 20

The middle of 15 and 25: add them, divide by 2.

20.

Next: 30.

Each midpoint is 10 more.

And so on.

2 Multiply m × f

Each number in a class counts as its midpoint.

So a class adds up to m times f.

20 times 3 is 60.

30 times 5 is 150.

The same for every row.

3 Add the columns

The f column: 24 numbers in all.

3 + 5 + 8 + 6 + 2 = 24

The m × f column: 950.

That is about the total of all the numbers.

60 + 150 + 320 + 300 + 120 = 950

4 Share equally

The mean shares the total equally: 950 divided by 24.

mean ≈ 95024

It is only an estimate: the midpoints stand in for the real numbers.

≈ : an estimate, from the midpoints

Careful!

Not divided by the 5 classes.

There are 24 numbers.

Careful: not 9505 ✗

950 divided by 24 is 39.5833.

mean ≈ 39.5833

The books round to one more decimal place than the data.

So the mean is about 39.6.

mean ≈ 39.6
1 decimal place: 1 more than the data

5 Check

Let's check: 39.6 times 24 is about 950, the total.

39.6 × 24 ≈ 950.4

And the mean is between the first and the last midpoints.

So it makes sense!

20 < 39.6 < 60

Let's look back.

First: find the midpoints.

Then: multiply m × f.

Then: add the columns.

Then: share equally.

Last: check.

Answer
1 decimal place: 1 more than the data

Your turn

Try this one yourself, then check:

Mean of 15–25: 5, 25–35: 3, 35–45: 8, 45–55: 3, 55–65: 3
Show the answer
mean ≈ 38.2

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