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Mean of grouped data 60-69: 2, 70-79: 6, 80-89: 9, 90-99: 4

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Step by step

The question

Question: find the mean of the grouped data with classes 60 to 69, 70 to 79, 80 to 89 and 90 to 99, and frequencies 2, 6, 9 and 4.

Mean of the grouped data

Each class is a range of numbers.

f is how many numbers are in it.

So 2 numbers are from 60 to 69.

f = how many, m = the middle of the class

1 Find the midpoints

We don't know the numbers themselves.

So each class uses its middle, m: the midpoint.

m = (60 + 69) ÷ 2 = 64.5

The middle of 60 and 69: add them, divide by 2.

64.5.

Next: 74.5.

Each midpoint is 10 more.

And so on.

2 Multiply m × f

Each number in a class counts as its midpoint.

So a class adds up to m times f.

64.5 times 2 is 129.

74.5 times 6 is 447.

The same for every row.

3 Add the columns

The f column: 21 numbers in all.

2 + 6 + 9 + 4 = 21

The m × f column: 1714.5.

That is about the total of all the numbers.

129 + 447 + 760.5 + 378 = 1714.5

4 Share equally

The mean shares the total equally: 1714.5 divided by 21.

mean ≈ 1714.521

It is only an estimate: the midpoints stand in for the real numbers.

≈ : an estimate, from the midpoints

Careful!

Not divided by the 4 classes.

There are 21 numbers.

Careful: not 1714.54 ✗

1714.5 divided by 21 is 81.6429.

mean ≈ 81.6429

The books round to one more decimal place than the data.

So the mean is about 81.6.

mean ≈ 81.6
1 decimal place: 1 more than the data

5 Check

Let's check: 81.6 times 21 is about 1714.5, the total.

81.6 × 21 ≈ 1713.6

And the mean is between the first and the last midpoints.

So it makes sense!

64.5 < 81.6 < 94.5

Let's look back.

First: find the midpoints.

Then: multiply m × f.

Then: add the columns.

Then: share equally.

Last: check.

Answer
1 decimal place: 1 more than the data

Your turn

Try this one yourself, then check:

Mean of 70–79: 1, 80–89: 8, 90–99: 8, 100–109: 2
Show the answer
mean ≈ 90.3

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