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Normal mean 100, sd 15: probability that x is between 85 and 115

Step by step, with the reason for every step · Normal probabilities with the z-table · University Statistics

Step by step

The question

Question: X is normal, with mean 100 and SD 15: what is the probability that X is between 85 and 115?

P(85 < X < 115): μ = 100, σ = 15

μ is the mean.

σ is the standard deviation, the SD.

μ = the mean, σ = the SD

1 Find z

z counts how many SDs x is from the mean: x minus the mean, over the SD.

z = x − μσ

85 minus 100 is −15.

Divided by 15, that is −1.

z = 85 − 10015 = −1515 = −1

And for 115: 115 minus 100 is 15.

Divided by 15, that is 1.

z = 115 − 10015 = 1515 = 1

2 Draw and shade

The bell: the mean, 100, in the middle.

85 is left of it.

115 is right of it.

We want X between 85 and 115.

We shade that part.

3 Read the table

The z-table gives the area to the left of z.

For z = −1: 0.1587.

For z = 1: 0.8413.

4 The area we want

Careful!

Both table numbers start at the far left.

So we take away the smaller one.

Careful: between: big area − small area

Between them: the bigger area minus the smaller one.

0.8413 minus 0.1587 is 0.6826.

P(85 < X < 115) = 0.8413 − 0.1587 = 0.6826

5 Check

Let's check: the three parts of the bell.

Left of z = −1: 0.1587.

Right of z = 1: 1 minus 0.8413, 0.1587.

left 0.1587 + middle 0.6826 + right 0.1587

They add up to 1, the whole bell.

So it is right!

= 1.0000

Let's look back.

First: find z.

Then: draw and shade.

Then: read the table.

Then: the area we want.

Last: check.

Answer
P(85 < X < 115) = 0.8413 − 0.1587 = 0.6826

Your turn

Try this one yourself, then check:

Find P(40 < X < 100): μ = 70, σ = 30
Show the answer
P(40 < X < 100) = 0.6826

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