Steply

Write 1 + i√3 in polar form

Step by step, with the reason for every step · Polar form of complex numbers, De Moivre's theorem · Precalculus

Step by step

The question

Question: write 1 + √3 i in polar form.

Polar form gives its distance from 0 and its angle.

1 + √3 i

1 Plot it

The complex plane: the real part goes across, the i part goes up.

1 + √3 i is the point (1, 1.73): 1 right, 1.73 up.

r is its distance from 0.

θ is its angle, from the positive real axis, turning counterclockwise.

2 Find r

Pythagoras: r = √(a² + b²), with a = 1 and b = √3.

r = √12 + (√3)2

1 squared is 1.

√3 squared is 3.

So r = 2.

r = √1 + 3 = √4 = 2

3 Find θ

The reference angle: tan is up over across, without the signs.

That is the tan of 60°, from the unit circle.

tan (ref) = √31 → 60°

The point is in quadrant I, so θ = 60°.

θ = 60°

4 Write it in polar form

Polar form is r(cos θ + i sin θ).

So 1 + √3 i = 2(cos 60° + i sin 60°).

= 1 + √3 i = 2(cos 60° + i sin 60°)

5 Check

Let's check: back to a + bi.

2 times cos 60° is 1.

2 × cos 60° = 2 × 12 = 1

2 times sin 60° is √3.

That is 1 + √3 i again.

Right!

2 × sin 60° = 2 × √32 = √3

Careful!

The angle is always measured from the positive real axis, turning counterclockwise.

Careful: θ from the positive real axis

Let's look back.

First: plot it.

Then: find r.

Then: find θ.

Then: write it in polar form.

Last: check.

Answer
= 1 + √3 i = 2(cos 60° + i sin 60°)

Your turn

Try this one yourself, then check:

Write 1 + i
Show the answer
1 + i = √2(cos 45° + i sin 45°)

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