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Write 2√3 + 2i in polar form

Step by step, with the reason for every step · Polar form of complex numbers, De Moivre's theorem · Precalculus

Step by step

The question

Question: write 2√3 + 2i in polar form.

Polar form gives its distance from 0 and its angle.

2√3 + 2i

1 Plot it

The complex plane: the real part goes across, the i part goes up.

2√3 + 2i is the point (3.46, 2): 3.46 right, 2 up.

r is its distance from 0.

θ is its angle, from the positive real axis, turning counterclockwise.

2 Find r

Pythagoras: r = √(a² + b²), with a = 2√3 and b = 2.

r = √(2√3)2 + 22

2√3 squared is 12.

2 squared is 4.

So r = 4.

r = √12 + 4 = √16 = 4

3 Find θ

The reference angle: tan is up over across, without the signs.

That is the tan of 30°, from the unit circle.

tan (ref) = 22√3 → 30°

The point is in quadrant I, so θ = 30°.

θ = 30°

4 Write it in polar form

Polar form is r(cos θ + i sin θ).

So 2√3 + 2i = 4(cos 30° + i sin 30°).

= 2√3 + 2i = 4(cos 30° + i sin 30°)

5 Check

Let's check: back to a + bi.

4 times cos 30° is 2√3.

4 × cos 30° = 4 × √32 = 2√3

4 times sin 30° is 2.

That is 2√3 + 2i again.

Right!

4 × sin 30° = 4 × 12 = 2

Careful!

The angle is always measured from the positive real axis, turning counterclockwise.

Careful: θ from the positive real axis

Let's look back.

First: plot it.

Then: find r.

Then: find θ.

Then: write it in polar form.

Last: check.

Answer
= 2√3 + 2i = 4(cos 30° + i sin 30°)

Your turn

Try this one yourself, then check:

Write 1 + √3 i
Show the answer
1 + √3 i = 2(cos 60° + i sin 60°)

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