Steply

Write -1 + i in polar form

Step by step, with the reason for every step · Polar form of complex numbers, De Moivre's theorem · Precalculus

Step by step

The question

Question: write −1 + i in polar form.

Polar form gives its distance from 0 and its angle.

−1 + i

1 Plot it

The complex plane: the real part goes across, the i part goes up.

−1 + i is the point (−1, 1): 1 left, 1 up.

r is its distance from 0.

θ is its angle, from the positive real axis, turning counterclockwise.

2 Find r

Pythagoras: r = √(a² + b²), with a = −1 and b = 1.

r = √(−1)2 + 12

−1 squared is 1.

1 squared is 1.

So r = √2.

r = √1 + 1 = √2

3 Find θ

The reference angle: tan is up over across, without the signs.

That is the tan of 45°, from the unit circle.

tan (ref) = 11 → 45°

The point is in quadrant II: 180° − 45°.

So θ = 135°.

θ = 180° − 45° = 135°

Careful!

The calculator's tan⁻¹ only gives angles in quadrants I and IV.

Our point is in quadrant II: look at the picture.

Careful: not θ = tan⁻¹(b ÷ a) = −45° ✗

4 Write it in polar form

Polar form is r(cos θ + i sin θ).

So −1 + i = √2(cos 135° + i sin 135°).

= −1 + i = √2(cos 135° + i sin 135°)

5 Check

Let's check: back to a + bi.

√2 times cos 135° is −1.

√2 × cos 135° = √2 × (−√22) = −1

√2 times sin 135° is 1.

That is −1 + i again.

Right!

√2 × sin 135° = √2 × √22 = 1

Let's look back.

First: plot it.

Then: find r.

Then: find θ.

Then: write it in polar form.

Last: check.

Answer
= −1 + i = √2(cos 135° + i sin 135°)

Your turn

Try this one yourself, then check:

Write −2 + 2i
Show the answer
−2 + 2i = 2√2(cos 135° + i sin 135°)

More from Polar form of complex numbers, De Moivre's theorem

The whole lesson: Polar form of complex numbers, De Moivre's theorem →