Steply

Write -1 + i√3 in polar form

Step by step, with the reason for every step · Polar form of complex numbers, De Moivre's theorem · Precalculus

Step by step

The question

Question: write −1 + √3 i in polar form.

Polar form gives its distance from 0 and its angle.

−1 + √3 i

1 Plot it

The complex plane: the real part goes across, the i part goes up.

−1 + √3 i is the point (−1, 1.73): 1 left, 1.73 up.

r is its distance from 0.

θ is its angle, from the positive real axis, turning counterclockwise.

2 Find r

Pythagoras: r = √(a² + b²), with a = −1 and b = √3.

r = √(−1)2 + (√3)2

−1 squared is 1.

√3 squared is 3.

So r = 2.

r = √1 + 3 = √4 = 2

3 Find θ

The reference angle: tan is up over across, without the signs.

That is the tan of 60°, from the unit circle.

tan (ref) = √31 → 60°

The point is in quadrant II: 180° − 60°.

So θ = 120°.

θ = 180° − 60° = 120°

Careful!

The calculator's tan⁻¹ only gives angles in quadrants I and IV.

Our point is in quadrant II: look at the picture.

Careful: not θ = tan⁻¹(b ÷ a) = −60° ✗

4 Write it in polar form

Polar form is r(cos θ + i sin θ).

So −1 + √3 i = 2(cos 120° + i sin 120°).

= −1 + √3 i = 2(cos 120° + i sin 120°)

5 Check

Let's check: back to a + bi.

2 times cos 120° is −1.

2 × cos 120° = 2 × (−12) = −1

2 times sin 120° is √3.

That is −1 + √3 i again.

Right!

2 × sin 120° = 2 × √32 = √3

Let's look back.

First: plot it.

Then: find r.

Then: find θ.

Then: write it in polar form.

Last: check.

Answer
= −1 + √3 i = 2(cos 120° + i sin 120°)

Your turn

Try this one yourself, then check:

Write −1 + i
Show the answer
−1 + i = √2(cos 135° + i sin 135°)

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