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Write √3 + i in polar form

Step by step, with the reason for every step · Polar form of complex numbers, De Moivre's theorem · Precalculus

Step by step

The question

Question: write √3 + i in polar form.

Polar form gives its distance from 0 and its angle.

√3 + i

1 Plot it

The complex plane: the real part goes across, the i part goes up.

√3 + i is the point (1.73, 1): 1.73 right, 1 up.

r is its distance from 0.

θ is its angle, from the positive real axis, turning counterclockwise.

2 Find r

Pythagoras: r = √(a² + b²), with a = √3 and b = 1.

r = √(√3)2 + 12

√3 squared is 3.

1 squared is 1.

So r = 2.

r = √3 + 1 = √4 = 2

3 Find θ

The reference angle: tan is up over across, without the signs.

That is the tan of 30°, from the unit circle.

tan (ref) = 1√3 → 30°

The point is in quadrant I, so θ = 30°.

θ = 30°

4 Write it in polar form

Polar form is r(cos θ + i sin θ).

So √3 + i = 2(cos 30° + i sin 30°).

= √3 + i = 2(cos 30° + i sin 30°)

5 Check

Let's check: back to a + bi.

2 times cos 30° is √3.

2 × cos 30° = 2 × √32 = √3

2 times sin 30° is 1.

That is √3 + i again.

Right!

2 × sin 30° = 2 × 12 = 1

Careful!

The angle is always measured from the positive real axis, turning counterclockwise.

Careful: θ from the positive real axis

Let's look back.

First: plot it.

Then: find r.

Then: find θ.

Then: write it in polar form.

Last: check.

Answer
= √3 + i = 2(cos 30° + i sin 30°)

Your turn

Try this one yourself, then check:

Write 1 + i
Show the answer
1 + i = √2(cos 45° + i sin 45°)

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