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A bag has 4 red and 5 blue marbles, 2 are picked at random, P(1 red…

Step by step, with the reason for every step · Probability with counting · Probability

Step by step

The question

Question: A bag has 4 red and 5 blue marbles.

2 marbles are picked at random.

What is the probability that 1 is a red and 1 is a blue?

The probability is the number of ways we want, over all the ways.

P(1 red, 1 blue) = ways we wantall ways

P stands for probability.

P = probability

1 Order: yes or no

Does order matter?

No.

Picking Ann, then Bo, is the same group as Bo, then Ann.

So we count groups: combinations.

= a group: order does not matter → nCr

2 Count all the ways

9 C 2: the top 2 numbers from 9 down, over 2 factorial.

all = 9C2 = 9 × 82 × 1

Before we multiply, we make the numbers smaller.

8 on top and 2 at the bottom: 8 divided by 2 is 4.

What is left: 9 times 4.

That is 36 ways.

all = 36
9 × 4 = 36

3 Count the ways we want

Picking 1 of 4 red: 4 ways.

red = 4C1 = 4

Picking 1 of 5 blue: 5 ways.

blue = 5C1 = 5

Each choice of red goes with each choice of blue.

So we multiply: 4 times 5 is 20.

we want = 4 × 5 = 20

Careful!

We need both at the same time: red and blue.

And means multiply, not add.

Careful: not 4 + 5 ✗

4 Write the fraction

20 ways we want, out of 36.

P(1 red, 1 blue) = 2036

5 Simplify

Both 20 and 36 can be divided by 4.

That makes it simpler.

P(1 red, 1 blue) = 20 ÷ 436 ÷ 4

So it is 5/9.

P(1 red, 1 blue) = 59

6 Check

Let's check another way: pick one at a time, in the order R, B.

Multiplied, that is 5/18.

RB: 49 × 58 = 518

But the 1 red and the 1 blue can come in 2 orders, each just as likely.

2 times that is 5/9.

The same.

So the answer is right!

2 orders: 2 × 518 = 59

Let's look back.

First: order: yes or no.

Then: count all the ways.

Then: count the ways we want.

Then: write the fraction.

Then: simplify.

Last: check.

Answer
P(1 red, 1 blue) = 59

Your turn

Try this one yourself, then check:

Show the answer
P(1 red, 1 blue) = 12

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