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Area of square with corners (-2, -3), (2, -3), (2, 1), (-2, 1)

Step by step, with the reason for every step · Polygons on the grid · Algebra 1

Step by step

The question

Question: find the area of the square with corners (−2, −3), (2, −3), (2, 1), (−2, 1).

square: (−2, −3), (2, −3), (2, 1), (−2, 1)

1 Plot the points

We put the corners on the grid.

Corner A is (−2, −3).

And so on.

We join them in order.

2 Find the side lengths

A B: the same y, so it goes across.

Its length is the bigger x minus the smaller: 2 minus −2 is 4.

= AB: 2 − (−2) = 4

Careful!

−2 is on the other side of 0.

Minus a negative is plus: 2 plus 2.

Careful: not 2 − 2 = 0 ✗

B C: the same x, so it goes up and down.

Its length is the bigger y minus the smaller: 1 minus −3 is 4.

= BC: 1 − (−3) = 4

3 Area

The area of a square is length times width.

= area = length × width

4 times 4 is 16 square units.

= area = 4 × 4 = 16 square units

4 Check

Let's check: count the squares inside.

4 rows of 4 squares: 16.

So the answer is right!

4 rows of 4 squares = 16 squares

Let's look back.

First: plot the points.

Then: find the side lengths.

Then: area.

Last: check.

Answer
= area = 4 × 4 = 16 square units

Your turn

Try this one yourself, then check:

square: (−1, −5), (3, −5), (3, −1), (−1, −1)
Show the answer
16 square units

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