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Area of triangle with corners (0, 3), (5, 3), (2, -1)

Step by step, with the reason for every step · Polygons on the grid · Algebra 1

Step by step

The question

Question: find the area of the triangle with corners (0, 3), (5, 3), (2, −1).

triangle: (0, 3), (5, 3), (2, −1)

1 Plot the points

We put the corners on the grid.

Corner A is (0, 3).

And so on.

We join them in order.

2 Find the base and height

base A B: the same y, so it goes across.

Its length is the bigger x minus the smaller: 5 minus 0 is 5.

= base AB: 5 − 0 = 5

The height goes straight up from C to the base line.

It goes from y = −1 to y = 3: 4 units.

= height: 3 − (−1) = 4

Careful!

−1 is on the other side of 0.

Minus a negative is plus.

Careful: not 3 − 1 = 2 ✗

3 Area

The area of a triangle is a half times base times height.

= area = 12 × base × height

Half of 5 times 4 is 10 square units.

= area = 12 × 5 × 4 = 10 square units

4 Check

Let's check: the rectangle around the base and the height is 5 by 4: 20 squares.

The triangle takes half of it: 10.

So the answer is right!

rectangle 5 × 4 = 20, half = 10

Let's look back.

First: plot the points.

Then: find the base and height.

Then: area.

Last: check.

Answer
= area = 12 × 5 × 4 = 10 square units

Your turn

Try this one yourself, then check:

triangle: (2, 1), (7, 1), (4, −3)
Show the answer
10 square units

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