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Domain of f(x) = 1/(x^2 - 4)

Step by step, with the reason for every step · Domain and range · Algebra 2

Step by step

The question

Question: find the domain of f(x) = 1/(x² − 4).

f(x) = 1x2 − 4

The domain is all the x's we can put in.

domain = the x's that can go in

1 Find where the bottom is 0

We can never divide by 0.

So the bottom can never be 0.

÷ 0: not allowed

Which x's make x² − 4 zero?

There is an x², so there can be two.

We solve x² − 4 = 0 with the quadratic lesson.

x2 − 4 = 0

Careful!

x² = 4 has two answers: 2 and −2.

Both make the bottom 0, so both are not allowed.

Careful: not x ≠ 2 only ✗

2 Get x² alone

There is no x term, so we get x² by itself.

To remove the − 4, we add 4 on both sides.

x2 − 4 + 4 = 0 + 4

0 + 4 = 4.

Now we have x² = 4.

x2 = 4

3 Square root of both sides

x squared is 4.

So x is the square root of 4, or minus it.

Minus times minus is plus, so the negative one works too.

x² = k → x = √k or x = −√k
2 × 2 = 4, (−2) × (−2) = 4

2 times 2 is 4.

So x = 2 or x = −2.

x = 2 or x = −2

4 Write the domain

Both are not allowed.

The domain is all real numbers except −2 and 2: x ≠ −2 and x ≠ 2.

domain : x ≠ −2 and x ≠ 2

5 Show it on a number line

Books also write the answer like this.

It is called interval notation.

A round bracket means the end is not in, like the open circle.

∞ means it goes on for ever.

∪ means or.

interval: (−∞, −2) ∪ (−2, 2) ∪ (2, ∞)

6 Check

Let's check.

Put 2 in: the bottom is 0.

Not allowed.

x = 2: 122 − 4 = 10 not allowed

Now 0: the bottom is −4, not 0.

It works.

x = 0: 102 − 4 = 1−4 = −14

Let's look back.

First: find where the bottom is 0.

Then: get x² alone.

Then: square root of both sides.

Then: write the domain.

Then: show it on a number line.

Last: check.

Answer
domain : x ≠ −2 and x ≠ 2

Your turn

Try this one yourself, then check:

domain of f(x) = 6x2 − 25
Show the answer
domain: x ≠ −5 and x ≠ 5

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