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Domain of f(x) = 5/(x^2 - 25)

Step by step, with the reason for every step · Domain and range · Algebra 2

Step by step

The question

Question: find the domain of f(x) = 5/(x² − 25).

f(x) = 5x2 − 25

The domain is all the x's we can put in.

domain = the x's that can go in

1 Find where the bottom is 0

We can never divide by 0.

So the bottom can never be 0.

÷ 0: not allowed

Which x's make x² − 25 zero?

There is an x², so there can be two.

We solve x² − 25 = 0 with the quadratic lesson.

x2 − 25 = 0

Careful!

x² = 25 has two answers: 5 and −5.

Both make the bottom 0, so both are not allowed.

Careful: not x ≠ 5 only ✗

2 Get x² alone

There is no x term, so we get x² by itself.

To remove the − 25, we add 25 on both sides.

x2 − 25 + 25 = 0 + 25

0 + 25 = 25.

Now we have x² = 25.

x2 = 25

3 Square root of both sides

x squared is 25.

So x is the square root of 25, or minus it.

Minus times minus is plus, so the negative one works too.

x² = k → x = √k or x = −√k
5 × 5 = 25, (−5) × (−5) = 25

5 times 5 is 25.

So x = 5 or x = −5.

x = 5 or x = −5

4 Write the domain

Both are not allowed.

The domain is all real numbers except −5 and 5: x ≠ −5 and x ≠ 5.

domain : x ≠ −5 and x ≠ 5

5 Show it on a number line

Books also write the answer like this.

It is called interval notation.

A round bracket means the end is not in, like the open circle.

∞ means it goes on for ever.

∪ means or.

interval: (−∞, −5) ∪ (−5, 5) ∪ (5, ∞)

6 Check

Let's check.

Put 5 in: the bottom is 0.

Not allowed.

x = 5: 552 − 25 = 50 not allowed

Now 0: the bottom is −25, not 0.

It works.

x = 0: 502 − 25 = 5−25 = −15

Let's look back.

First: find where the bottom is 0.

Then: get x² alone.

Then: square root of both sides.

Then: write the domain.

Then: show it on a number line.

Last: check.

Answer
domain : x ≠ −5 and x ≠ 5

Your turn

Try this one yourself, then check:

domain of f(x) = 4x2 − 4
Show the answer
domain: x ≠ −2 and x ≠ 2

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