Steply

Domain of f(x) = 3/(x^2 - 9)

Step by step, with the reason for every step · Domain and range · Algebra 2

Step by step

The question

Question: find the domain of f(x) = 3/(x² − 9).

f(x) = 3x2 − 9

The domain is all the x's we can put in.

domain = the x's that can go in

1 Find where the bottom is 0

We can never divide by 0.

So the bottom can never be 0.

÷ 0: not allowed

Which x's make x² − 9 zero?

There is an x², so there can be two.

We solve x² − 9 = 0 with the quadratic lesson.

x2 − 9 = 0

Careful!

x² = 9 has two answers: 3 and −3.

Both make the bottom 0, so both are not allowed.

Careful: not x ≠ 3 only ✗

2 Get x² alone

There is no x term, so we get x² by itself.

To remove the − 9, we add 9 on both sides.

x2 − 9 + 9 = 0 + 9

0 + 9 = 9.

Now we have x² = 9.

x2 = 9

3 Square root of both sides

x squared is 9.

So x is the square root of 9, or minus it.

Minus times minus is plus, so the negative one works too.

x² = k → x = √k or x = −√k
3 × 3 = 9, (−3) × (−3) = 9

3 times 3 is 9.

So x = 3 or x = −3.

x = 3 or x = −3

4 Write the domain

Both are not allowed.

The domain is all real numbers except −3 and 3: x ≠ −3 and x ≠ 3.

domain : x ≠ −3 and x ≠ 3

5 Show it on a number line

Books also write the answer like this.

It is called interval notation.

A round bracket means the end is not in, like the open circle.

∞ means it goes on for ever.

∪ means or.

interval: (−∞, −3) ∪ (−3, 3) ∪ (3, ∞)

6 Check

Let's check.

Put 3 in: the bottom is 0.

Not allowed.

x = 3: 332 − 9 = 30 not allowed

Now 0: the bottom is −9, not 0.

It works.

x = 0: 302 − 9 = 3−9 = −13

Let's look back.

First: find where the bottom is 0.

Then: get x² alone.

Then: square root of both sides.

Then: write the domain.

Then: show it on a number line.

Last: check.

Answer
domain : x ≠ −3 and x ≠ 3

Your turn

Try this one yourself, then check:

domain of f(x) = 2x2 − 4
Show the answer
domain: x ≠ −2 and x ≠ 2

More from Domain and range

The whole lesson: Domain and range →