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Domain of f(x) = 1/(x^2 + x - 6)

Step by step, with the reason for every step · Domain and range · Algebra 2

Step by step

The question

Question: find the domain of f(x) = 1/(x² + x − 6).

f(x) = 1x2 + x − 6

The domain is all the x's we can put in.

domain = the x's that can go in

1 Find where the bottom is 0

We can never divide by 0.

So the bottom can never be 0.

÷ 0: not allowed

Which x's make x² + x − 6 zero?

There is an x², so there can be two.

We solve x² + x − 6 = 0 with the quadratic lesson.

x2 + x − 6 = 0

Careful!

The bottom is 0 when either bracket is 0.

So two x's are not allowed.

Careful: each bracket = 0 gives an x that is not allowed

2 Factor

We need two numbers.

They multiply to −6, and they add to 1.

? × ? = −6
? + ? = 1

They multiply to a minus number, so one number is plus and one is minus.

They add to a plus number, so the bigger one is plus.

× is − → one +, one −; bigger one +

We list the pairs that make 6, smallest first.

We take the smaller from the bigger.

We need 1.

2 and 3 give 1.

Yes!

With the signs: −2 and 3.

1 × 6: 6 − 1 = 5
2 × 3: 3 − 2 = 1 ✓

So it is (x − 2)(x + 3) = 0.

(x − 2)(x + 3) = 0

3 One bracket is 0

Two numbers multiply to 0.

That only happens if one of them is 0.

So one bracket must be 0.

A × B = 0 → A = 0 or B = 0

We make each bracket 0.

Two small equations.

x − 2 = 0 or x + 3 = 0

In x − 2 = 0, we add 2 on both sides.

In x + 3 = 0, we take away 3 on both sides.

x − 2 + 2 = 0 + 2 or x + 3 − 3 = 0 − 3

So x = 2 or x = −3.

x = 2 or x = −3

4 Write the domain

Both are not allowed.

The domain is all real numbers except −3 and 2: x ≠ −3 and x ≠ 2.

domain : x ≠ −3 and x ≠ 2

5 Show it on a number line

Books also write the answer like this.

It is called interval notation.

A round bracket means the end is not in, like the open circle.

∞ means it goes on for ever.

∪ means or.

interval: (−∞, −3) ∪ (−3, 2) ∪ (2, ∞)

6 Check

Let's check.

Put 2 in: the bottom is 0.

Not allowed.

x = 2: 122 + 2 − 6 = 10 not allowed

Now 0: the bottom is −6, not 0.

It works.

x = 0: 102 + 0 − 6 = 1−6 = −16

Let's look back.

First: find where the bottom is 0.

Then: factor.

Then: one bracket is 0.

Then: write the domain.

Then: show it on a number line.

Last: check.

Answer
domain : x ≠ −3 and x ≠ 2

Your turn

Try this one yourself, then check:

domain of f(x) = 5x2 − 2x − 8
Show the answer
domain: x ≠ −2 and x ≠ 4

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