Steply

Work out the gradient of the straight line through (−1, 4) and (3…

Step by step, with the reason for every step · GCSE Maths Foundation Paper 3 · GCSE Maths

Step by step

The question

Question: find the slope of the line through (−1, 4) and (3, 12).

(−1, 4) and (3, 12)

1 Plot the points

Draw the grid: the x-axis goes across, and the y-axis goes up and down.

They meet at 0, a point called the origin.

Put both points on the grid: (−1, 4)

and (3, 12).

Draw the line through them.

2 Rise and run

We start at the point on the left.

Run: how far we go right.

From x = −1 to x = 3 is 4.

Rise: how far we go up.

From y = 4 to y = 12 is 8.

3 Use the formula

We call the slope m.

m = rise over run.

m = riserun

The top is the change in y: second y minus first y.

The bottom is the change in x: second x minus first x.

It gives the same rise and run, without counting on the grid.

m = y2 − y1x2 − x1

Put the numbers in.

The second point is (3, 12).

The first point is (−1, 4).

m = 12 − 43 − (−1)

Taking away a negative is the same as adding.

− (−) = +

So it becomes (12 − 4)/(3 + 1).

m = 12 − 43 + 1

12 minus 4 is 8.

3 plus 1 is 4.

The same rise and run as on the grid.

m = 84

8 divided by 4 is 2.

So m = 2.

m = 2

A positive slope goes up from left to right.

For every 1 step to the right, it goes up 2.

4 Check

Let's check: take the points the other way round.

4 − 12 is −8.

−1 − 3 is −4.

m = 4 − 12−1 − 3 = −8−4

Minus over minus is plus.

We get 2 again.

The same slope!

= 2

Let's look back.

First: plot the points.

Then: rise and run.

Then: use the formula.

Last: check.

Answer
m = 2

Your turn

Try this one yourself, then check your answer:

Find the slope of the line through (−1, 8) and (7, 16)
Show the answer
m = 1

More from GCSE Maths Foundation Paper 3

The whole lesson: GCSE Maths Foundation Paper 3 →