Steply

Write 6(cos 330° + i sin 330°) in rectangular form

Step by step, with the reason for every step · Polar form of complex numbers, De Moivre's theorem · Precalculus

Step by step

The question

Question: write 6(cos 330° + i sin 330°) in rectangular form.

Rectangular form is a + bi.

6(cos 330° + i sin 330°)

1 Read r and θ

The number in front is the distance: r = 6.

The angle is θ = 330°.

r = 6, θ = 330°

2 Find cos θ and sin θ

From the unit circle: cos 330° = √3/2.

cos 330° = √32

And sin 330° = −1/2.

sin 330° = −12

Careful!

cos gives the real part, across.

sin gives the i part, up.

Do not swap them.

Careful: cos goes with the real part, sin with i

3 Multiply out

Put them in.

= 6(√32 + (−12)i)

Multiply each part by 6: 3√3 − 3i.

= 3√3 − 3i

4 Check

Let's check the distance by Pythagoras: the square root of 27 plus 9 is 6.

That is r.

Right!

r = √27 + 9 = 6

Let's look back.

First: read r and θ.

Then: find cos θ and sin θ.

Then: multiply out.

Last: check.

Answer
= 3√3 − 3i

Your turn

Try this one yourself, then check:

2(cos 300° + i sin 300°)
Show the answer
1 − √3 i

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