Steply

Write -2 - 2i in polar form

Step by step, with the reason for every step · Polar form of complex numbers, De Moivre's theorem · Precalculus

Step by step

The question

Question: write −2 − 2i in polar form.

Polar form gives its distance from 0 and its angle.

−2 − 2i

1 Plot it

The complex plane: the real part goes across, the i part goes up.

−2 − 2i is the point (−2, −2): 2 left, 2 down.

r is its distance from 0.

θ is its angle, from the positive real axis, turning counterclockwise.

2 Find r

Pythagoras: r = √(a² + b²), with a = −2 and b = −2.

r = √(−2)2 + (−2)2

−2 squared is 4.

−2 squared is 4.

So r = 2√2.

r = √4 + 4 = √8 = 2√2

3 Find θ

The reference angle: tan is up over across, without the signs.

That is the tan of 45°, from the unit circle.

tan (ref) = 22 → 45°

The point is in quadrant III: 180° + 45°.

So θ = 225°.

θ = 180° + 45° = 225°

Careful!

The calculator's tan⁻¹ only gives angles in quadrants I and IV.

Our point is in quadrant III: look at the picture.

Careful: not θ = tan⁻¹(b ÷ a) = 45° ✗

4 Write it in polar form

Polar form is r(cos θ + i sin θ).

So −2 − 2i = 2√2(cos 225° + i sin 225°).

= −2 − 2i = 2√2(cos 225° + i sin 225°)

5 Check

Let's check: back to a + bi.

2√2 times cos 225° is −2.

2√2 × cos 225° = 2√2 × (−√22) = −2

2√2 times sin 225° is −2.

That is −2 − 2i again.

Right!

2√2 × sin 225° = 2√2 × (−√22) = −2

Let's look back.

First: plot it.

Then: find r.

Then: find θ.

Then: write it in polar form.

Last: check.

Answer
= −2 − 2i = 2√2(cos 225° + i sin 225°)

Your turn

Try this one yourself, then check:

Write −√3 − i
Show the answer
−√3 − i = 2(cos 210° + i sin 210°)

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