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A bag has 3 red and 5 blue marbles, two are picked without…

Step by step, with the reason for every step · Conditional probability · Probability

Step by step

The question

Question: A bag has 3 red and 5 blue marbles.

Two marbles are picked, one after the other.

The first one is not put back.

What is the probability the second is red, given the first is red?

The line means given.

We already know the first is red.

P(2nd red | 1st red) = ?

P stands for probability.

The line stands for given.

P = probability, | = given

1 Draw a tree

2 Go along the given branch

Given the first is red: we go along the red branch only.

3 Read the next branch

From there, red is the branch with 2/7.

So the probability is 2/7.

One red is already out of the bag.

P(2nd red | 1st red) = 27

Careful!

That is the probability of both.

Here the first is already red: we only need the second branch.

Careful: not 38 × 27 ✗

4 Check

Let's check with the rule: the probability of both, divided by the probability of the first being red.

P(both) ÷ P(1st red) = (38 × 27) ÷ 38

Times 3/8, then divided by 3/8: we are back to 2/7.

The same.

So the answer is right!

= 27

Let's look back.

First: draw a tree.

Then: go along the given branch.

Then: read the next branch.

Last: check.

Answer
Careful: not 38 × 27 ✗

Your turn

Try this one yourself, then check:

Show the answer
P(2nd red | 1st red) = 17

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