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Domain and range of f(x) = 4/(x + 1) - 2

Step by step, with the reason for every step · Domain and range · Algebra 2

Step by step

The question

Question: find the domain and range of f(x) = 4/(x + 1), − 2.

f(x) = 4x + 1 − 2

The domain is all the x's we can put in.

The range is all the y's that can come out.

domain = the x's that can go in
range = the y's that can come out

1 Find where the bottom is 0

We can never divide by 0.

So the bottom can never be 0.

÷ 0: not allowed

The bottom x + 1 is 0 when x = −1: −1 plus 1 is 0.

x + 1 = 0 → x = −1

So the domain is all real numbers except −1: x ≠ −1.

x ≠ −1

Now the range: which y's can come out?

2 What a fraction can be

A fraction is 0 only when its top is 0.

Here the top is 4.

So 4/(x + 1) is never 0.

It can be any other number.

a fraction is 0 only when its top is 0
the top is 4: never 0

Careful!

−1 is the x that can't go in.

The range is about the y's that come out.

Careful: not range: y ≠ −1 ✗

So 4/(x + 1) ≠ 0.

4x + 1 ≠ 0

3 Take away the 2

In f(x), − 2 comes after.

So we take away 2.

We do it on both sides, so the sign stays true.

4x + 1 − 2 ≠ 0 − 2

The left side is f(x), the y.

So y ≠ −2.

Every y except −2 comes out.

y ≠ −2

4 See it on the graph

Draw the grid.

Here is the graph of f(x) = 4/(x + 1), − 2.

It never touches x = −1: that x can't go in.

And it never touches y = −2: that y never comes out.

5 Check

Let's check.

Any other y can come out: x = 0 gives y = 2.

x = 0: 40 + 1 − 2 = 4 − 2 = 2

But y = −2 would need 4/(x + 1) = 0, and the top 4 is never 0.

So −2 never comes out.

y = −2: 4x + 1 = 0 never true

Let's look back.

First: find where the bottom is 0.

Then: what a fraction can be.

Then: take away the 2.

Then: see it on the graph.

Last: check.

Answer
y ≠ −2

Your turn

Try this one yourself, then check:

domain and range of f(x) = 3x + 3 − 4
Show the answer
domain: x ≠ −3, range: y ≠ −4

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