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Domain of f(x) = 3/(x(x + 4))

Step by step, with the reason for every step · Domain and range · Algebra 2

Step by step

The question

Question: find the domain of f(x) = 3/(x² + 4x).

f(x) = 3x2 + 4x

The domain is all the x's we can put in.

domain = the x's that can go in

1 Find where the bottom is 0

We can never divide by 0.

So the bottom can never be 0.

÷ 0: not allowed

Which x's make x² + 4x zero?

There is an x², so there can be two.

We solve x² + 4x = 0 with the quadratic lesson.

x2 + 4x = 0

Careful!

The bottom is 0 when either bracket is 0.

So two x's are not allowed.

Careful: each bracket = 0 gives an x that is not allowed

2 Factor

There is no plain number.

Both parts have x in them.

So we take x out.

x² = x × x, 4x = x × 4

So it is x(x + 4) = 0.

x(x + 4) = 0

3 One bracket is 0

x times the bracket is 0.

That only happens if one of them is 0.

A × B = 0 → A = 0 or B = 0

We make each part 0.

Two small equations.

x = 0 or x + 4 = 0

x = 0 is done already.

In x + 4 = 0, we take away 4 on both sides.

x = 0 or x + 4 − 4 = 0 − 4

So x = 0 or x = −4.

x = 0 or x = −4

4 Write the domain

Both are not allowed.

The domain is all real numbers except −4 and 0: x ≠ −4 and x ≠ 0.

domain : x ≠ −4 and x ≠ 0

5 Show it on a number line

Books also write the answer like this.

It is called interval notation.

A round bracket means the end is not in, like the open circle.

∞ means it goes on for ever.

∪ means or.

interval: (−∞, −4) ∪ (−4, 0) ∪ (0, ∞)

6 Check

Let's check.

Put 0 in: the bottom is 0.

Not allowed.

x = 0: 302 + 4(0) + 0 = 30 not allowed

Now 1: the bottom is 5, not 0.

It works.

x = 1: 312 + 4(1) + 0 = 35

Let's look back.

First: find where the bottom is 0.

Then: factor.

Then: one bracket is 0.

Then: write the domain.

Then: show it on a number line.

Last: check.

Answer
domain : x ≠ −4 and x ≠ 0

Your turn

Try this one yourself, then check:

domain of f(x) = 6x2 + x − 2
Show the answer
domain: x ≠ −2 and x ≠ 1

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