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A bag has 5 red and 3 blue marbles, two are picked without…

Step by step, with the reason for every step · Conditional probability · Probability

Step by step

The question

Question: A bag has 5 red and 3 blue marbles.

Two marbles are picked, one after the other.

The first one is not put back.

What is the probability the second is blue, given the first is blue?

The line means given.

We already know the first is blue.

P(2nd blue | 1st blue) = ?

P stands for probability.

The line stands for given.

P = probability, | = given

1 Draw a tree

2 Go along the given branch

Given the first is blue: we go along the blue branch only.

3 Read the next branch

From there, blue is the branch with 2/7.

So the probability is 2/7.

One blue is already out of the bag.

P(2nd blue | 1st blue) = 27

Careful!

That is the probability of both.

Here the first is already blue: we only need the second branch.

Careful: not 38 × 27 ✗

4 Check

Let's check with the rule: the probability of both, divided by the probability of the first being blue.

P(both) ÷ P(1st blue) = (38 × 27) ÷ 38

Times 3/8, then divided by 3/8: we are back to 2/7.

The same.

So the answer is right!

= 27

Let's look back.

First: draw a tree.

Then: go along the given branch.

Then: read the next branch.

Last: check.

Answer
Careful: not 38 × 27 ✗

Your turn

Try this one yourself, then check:

Show the answer
P(2nd blue | 1st blue) = 49

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